"An Olympic long jumper leaves the ground at an angle of 23 and travels through the air for a horizontal distance of 8.7 m during 2.50 s before landing. What is the takeoff speed V_0 of the jumper? (tip: this problem requires two steps) A. 3.78 m/s B. 3.48 m/s C. 8.91 m/s D. 0.287 m/s"

adailymonthly7ve

adailymonthly7ve

Answered question

2022-12-18

An Olympic long jumper leaves the ground at an angle of 23 and travels through the air for a horizontal distance of 8.7 mduring 2.50 s before landing. What is the takeoff speed V 0 of the jumper? (tip: this problem requires two steps)
A. 3.78 m/s
B. 3.48 m/s
C. 8.91 m/s
D. 0.287 m/s

Answer & Explanation

Rohan Horn

Rohan Horn

Beginner2022-12-19Added 3 answers

If V is the take off velocity
Horizontal components of velocity V x = V cos θ = 8.7 m 2.5 sec = 3.480 m / s
V = 3.480 cos θ = 3.7805 m / s
Choice is A

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