Gingan7mhd

2023-03-28

How to find the vertex of the parabola by completing the square ${x}^{2}-6x+8=y$?

peminggirotnn

Beginner2023-03-29Added 5 answers

$y={x}^{2}-6x+8={x}^{2}-6x+9-1={(x-3)}^{2}-1$

This has its vertex where $x-3=0$, that is $x=3$

When $x=3$ we have $y={0}^{2}-1=-1$

Hence the vertex is at $(3,-1)$

This has its vertex where $x-3=0$, that is $x=3$

When $x=3$ we have $y={0}^{2}-1=-1$

Hence the vertex is at $(3,-1)$

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