The second member of Balmer series of hydrogen atom has wavelength of 4861 × 10 − 10 m. Calculate the wavelength of third member of Balmer series

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The second member of Balmer series of hydrogen atom has wavelength of   4861  ×      10          −      10       m. Calculate the wavelength of third member of Balmer series

stafninumfu1tf · Accepted Answer

To find−Wavelength of 3rd line in Balmer series (      λ    r  ) = ?Given −Wavelength 2nd line in Balmer series       λ    β    =  4861  ×      10          −      10       mThe second number of Balmer series i.e.       H          β       line and third number is       H          γ       lineFor       H          β       line       n    i    =  2  ,         n    f    =  4Therefore−      1          λ              ρ              =  R  [      1          2      2        −      1          4      2        ]        1          λ              ρ              =  R  [      1    4    −      1    16    ]        1          λ              ρ              =            3      R        16  and      1          λ              ρ              =  R  [      1          2      2        −      1          5      2        ]        1          λ              ρ              =  R  [      1    4    −      1    25    ]        1          λ              ρ              =            21      R        100  Dividing equations:Therefore -            λ              γ                    λ              ρ              =      300          16      ×      21                    λ              γ                    λ              ρ              =      25    28          λ          γ        =      25    28    ×      λ          β              λ          γ        =      25    28    ×  4861  ×      10          −      10              λ          γ        =  4340  ×      10          −      10        m

The second member of Balmer series of hydrogen atom has wavelength of 4861 ×

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