What is the series limit for the Balmer series? (The series limit, like the name suggests, is the last line of the given series - the smallest wavelength that's still part of the same set of spectral lines) A. 364.6nm B. 121.6nm C.656.3nm D. 385.4nm

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What is the series limit for the Balmer series?  (The series limit, like the name suggests, is the last line of the given series - the smallest wavelength that&#039;s still part of the same set of spectral lines) A. 364.6nm B. 121.6nm C.656.3nm D. 385.4nm

Keely Franco · Accepted Answer

Rydberg is our knight in shining armour, again! We know, for the Balmer series       n    1    =  2. The series limit, or the very last line in the series, will be obtained by putting       n    2    =  ∞. Thus the Balmer series limit can be found as –      1          λ      ∞        =  R  (      1          2      2        −      1          ∞      2        )  =      R    4        m          −      1        }Rightarrow lambda_infty=frac4Rm=3.646times10^{−7}m=364.6nm.Show External URL Show Embeded Code Hide MathML Code⇒λ∞=4Rm=3.646×10−7m=364.6nm.  ⇒      λ    ∞    =      4    R    m  =  3.646  ×      10          −      7        m  =  364.6  n  m  . Option (a) is correct! The significance of the wavelength is, it’s the Balmer line with the smallest wavelength. The next line with a smaller wavelength will be the first line of the Lyman series, which is 121.6 nm. This essentially means, there will be no spectral lines in the range 121.6 nm - 364.6nm.

What is the series limit for the Balmer series? (The series limit, like the name suggests, is the last line of the given series - the smallest wavelength that's still part of the same set of spectral lines) A. 364.6nm B. 121.6nm C.656.3nm D. 385.4nm

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