How do you find the limit of (e^x + x)^(1/x) as x approaches 0 using l'hospital's rule?

Corbin Atkinson

Corbin Atkinson

Answered question

2023-02-05

How to find the limit of ( e x + x ) 1 x as x approaches 0 using l'hospital's rule?

Answer & Explanation

alvernesaky4

alvernesaky4

Beginner2023-02-06Added 7 answers

Rewrite it as e ln ( e x + x ) 1 x and find lim x 0 ln ( e x + x ) 1 x .
Solution: lim x 0 ln ( e x + x ) 1 x = lim x 0 1 x ln ( e x + x )
= lim x 0 ln ( e x + x ) x
This limit has indeterminate form 0 0 . ( ln ( e 0 + 0 ) = ln 1 = 0 )
Apply l"Hospital's rule:
Find
lim x 0 1 e x + x ( e x + 1 ) 1 = lim x 0 e x + 1 e x + x = 2 .
As x 0 , the exponent ln ( e x + x ) 1 x 2 , thus
lim x 0 ( e x + x ) 1 x = lim x 0 e ln ( e x + x ) 1 x = e 2

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