Let y = f(x) be a twice-differentiable function such that f(1) = 2 and . What is the value of (d^2y)/(dx^2) at x = 1.

Ryland Solomon

Ryland Solomon

Answered question

2023-02-05

Let y = f(x) be a twice-differentiable function such that f(1) = 2 and . What is the value of d 2 y d x 2 at x = 1.

Answer & Explanation

Dakota Fields

Dakota Fields

Beginner2023-02-06Added 3 answers

d y d x = y 2 + 3
y=2 when x=1, so y = 2 d y d x = 2 2 + 3 = 7
d 2 y d x 2 = 2 y d y d x
x=1, d 2 y d x 2 = 2 ( 2 ) ( 7 ) = 28
Custodio88j

Custodio88j

Beginner2023-02-07Added 1 answers

d y d x = y 2 + 3 d 2 y d x 2 = 2 y y = 2 y ( y 2 + 3 )
d 2 y d x 2 = 2 × 2 ( 2 2 + 3 ) = 28

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