How to find the critical numbers of g(theta) = 4theta-tan(theta)?

markezop78

markezop78

Answered question

2023-02-12

How to find the critical numbers of g ( θ ) = 4 θ - tan ( θ ) ?

Answer & Explanation

tabuaa5q

tabuaa5q

Beginner2023-02-13Added 7 answers

Extrema
g ( θ ) = 4 - 1 cos 2 ( θ ) = 0
or
cos 2 ( θ ) = 1 4
cos ( θ ) = ± 1 2
That is
θ = π 3
θ = 5 π 3
for cos ( θ ) = 1 2
and
θ = 2 π 3
θ = 4 π 3
for cos ( θ ) = - 1 2
g ( θ ) = - ( - 2 ) cos - 3 ( θ ) ( - sin ( θ ) ) = - 2 cos - 3 ( θ ) sin ( θ )
graph{4x-tan(x) [-7, 7, -7, 7]}
graph{sin(x)/cos(x)^3 [-7, 7, -30, 30]}
The second derivative of g, as shown on the bottom plot, changes sign at x = 0, as anticipated. Therefore x=0 is an inflection point. The extrema are true extrema. The second derivative does not change sign at the extrema. If it did, these would not be extrema but saddle points.

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