How do you find the limit of x^2 sin(1/x) as x approaches 0?

Reblausvtct

Reblausvtct

Answered question

2023-02-15

How to find the limit of x 2 sin ( 1 x ) as x approaches 0?

Answer & Explanation

Julien Zavala

Julien Zavala

Beginner2023-02-16Added 7 answers

Make use of the squeeze theorem.
We have from trigonometry that
- 1 sin ( 1 x ) < - 1
Important: for lim x 0 we don't care what happens when x = 0 .
Since x < 2 > 0 for all x 0 , we can multiply through by x 2 to get
- x 2 = x 2 sin ( 1 x ) x 2
Clearly lim x 0 ( - x 2 ) = 0 and lim x 0 x 2 = 0 , therefore, by the squeeze theorem,
lim x 0 x 2 sin ( 1 x ) = 0

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