"Find the first partial derivatives. g(x,y)=2exy gx(x,y)= gy(x,y)=" solved and explained

Zoe Oneal

Answered question

2021-05-28

Find the first partial derivatives.

g (x, y) = 2 e^{\frac{x}{y}}

g_{x} (x, y) =

g_{y} (x, y) =

au4gsf

Skilled2021-05-29Added 95 answers

Step 1
Find partial derivative.

g (x, y) = 2 e^{\frac{x}{y}}

Step 2

g_{x} (x, y) = \frac{\partial g}{\partial x}

= 2 e^{\frac{x}{y}} \cdot (\frac{1}{y})

g_{x} (x, y) = \frac{2}{y} e^{\frac{x}{y}}

g_{y} (x, y) = \frac{\partial g}{\partial y}

= 2 e^{\frac{x}{y}} \cdot (\frac{- x}{y^{2}})

g_{y} (x, y) = \frac{- 2 x}{y^{2}} e^{\frac{x}{y}}

Jeffrey Jordon

Expert2021-11-20Added 2605 answers

Answer is given below (on video)

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