Find the first and second derivatives involving differences, products, and quotients. y=(\frac{1+3x}{3x})(3-x)

naivlingr

naivlingr

Answered question

2021-05-19

Find the first and second derivatives involving differences, products, and quotients.
y=(1+3x3x)(3x)

Answer & Explanation

lamusesamuset

lamusesamuset

Skilled2021-05-20Added 93 answers

y=(1+3x3x)(3x)
Using product rule
dydx=(3x)(3.3x3(1+3x)9x2)+(1+3x3x)(1)
dydx=(3x)(13x2)(1+3x3x)
dydx=x33x2(3x+13x)=x33x2x3x2=1x2x2
similarly
d2ydx2=x2(2x)2x(1x2)x4=2x3+2x+2x3x4=2x3
Jeffrey Jordon

Jeffrey Jordon

Expert2021-11-24Added 2605 answers

Answer is given below (on video)

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