Find the local maximum and minimum values and saddle points of the function. If you have three-dimensional graphing software, graph the function with a domain and viewpoint that reveal all the important aspects of the function. f(x,y)=x^3-6xy+8y^3

Falak Kinney

Falak Kinney

Answered question

2021-05-14

Find the local maximum and minimum values and saddle points of the function. If you have three-dimensional graphing software, graph the function with a domain and viewpoint that reveal all the important aspects of the function.
f(x,y)=x36xy+8y3

Answer & Explanation

lamanocornudaW

lamanocornudaW

Skilled2021-05-15Added 85 answers

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Jeffrey Jordon

Jeffrey Jordon

Expert2021-09-29Added 2605 answers

Find the critical points using the given function, and identify whether they are the local minimum, maximum, or saddle point.

f(x,y)=x36xy+8y3

Identify first derivatives in terms of Fx(x,y) and Fy(x,y)

Fx(x,y)=3x26y

Fy(x,y)=6x+24y2

Find the critical points of x by solving for y in Fx and substituting result into Fy

Fx(x,y)=3x26y3x2=6y12x2=y

Fy(x,y)=6x+24(12x2)26x+6x4

=6x(x31)=0x=0 and x=1

Find the critical values of y associated with the critical values found for x by substituting into Fx

Fx(0,y)=3x26y0=6yy=0

Fx(1,y)=3x26y3=6yy=12

using Fx(x,y) and Fy(x,y) find the second derivatives in terms of Fxx(x,y), Fyy(x,y) and Fxy(x,y)

Fxx(x,y)=6x

Fyy(x,y)=48y

Fxy=6

When the rules are defined, use the second derivative test.

D=D(x,y)=Fxx(x,y)Fyy(x,y)(Fxyx,y)2

D>0 and Fxx(x,y)<0, then F(x,y) is local maximum D<0 then F(x,y) is a saddle point

The critical points identified as (0,0) and (1,12) are to be used to solve

D=D(0,0)=00(6)2=36; D=D(1,12)=624(6)2=108

Compare D values of Fxx(x,y) to indentify critical points as local maximum, minimum or saddle points

D=D(0,0)=36D<0 Saddle point

D=D(1,12)=108, Fxx(1,12)>0

D(1,12) is local minimum

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