Please, find the integral int (frac{1}{sqrt(2x-1)})^2 dx

Cabiolab

Cabiolab

Answered question

2021-09-12

Please, find the integral (12x1)2dx

Answer & Explanation

saiyansruleA

saiyansruleA

Skilled2021-09-13Added 110 answers

(12x1)2dx=12x1)dx
By using substitution u=2x1 we have du=2dx and so dx=du2. So, the given integral becomes:
12udu=121udu=12ln|u|
Having back the value of u we get:
(12x1)2dx=12ln|2x1|+C

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