Find the limit: \lim_{x\to\infty}(\frac{1-x^3}{x^2+7x})^5

shadsiei

shadsiei

Answered question

2021-10-15

Find the limit:
limx(1x3x2+7x)5

Answer & Explanation

sovienesY

sovienesY

Skilled2021-10-16Added 89 answers

The given limit expression is limx((1x3x2+7x)5)
Find the limit as follows:
limx((1x3x2+7x)5)=(limx(1x3x2+7x))5
=(limx(1x2x3x2x2x2+7xx2))5
=(limx(1x2x1+7x)5
=(limx(1x2x)limx(1+7x))
=(1)5
=

Jeffrey Jordon

Jeffrey Jordon

Expert2022-08-30Added 2605 answers

Answer is given below (on video)

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