Does \lim_{(x,y)\to(3,-1)}\frac{(x-3)(y+1)}{(x-3)^2+(y+1)^2} exist?

Carol Gates

Carol Gates

Answered question

2021-10-25

Does lim(x,y)(3,1)(x3)(y+1)(x3)2+(y+1)2 exist?

Answer & Explanation

jlo2niT

jlo2niT

Skilled2021-10-26Added 96 answers

Given that lim(x,y)(3,1)(x3)(y+1)(x3)2+(y+1)2
The value of the limit lim(x,y)(3,1)(x3)(y+1)(x3)2+(y+1)2 do not exist as the denominator becomes 0.
Evaluate lim(x,y)(3,1)(x3)(y+1)(x3)2+(y+1)2 as shown below
lim(x,y)(3,1)(x3)(y+1)(x3)2+(y+1)2=(03)(0+1)(03)2+(0+1)2
=(3)(1)9+1
=310
Therefore, the limits when x=0 and y=0 lim(x,y)(3,1)(x3)(y+1)(x3)2+(y+1)2=310.

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?