Find the derivative of the function. y=ln|sec x+tan x|

foass77W

foass77W

Answered question

2021-02-19

Find the derivative of the function. y=ln|secx+tanx|

Answer & Explanation

Roosevelt Houghton

Roosevelt Houghton

Skilled2021-02-20Added 106 answers

y=ln|secx+tanx|
dydx=d(ln|secx+tanx|)dx
dydx=1(secx+tanx)dsecx+tanxdx
dydx=1(secx+tanx)(secxtanx+sec2x)
dydx=1(secx+tanx)secx(tanx+secx)
dydx=(secx+tanx)(secx+tanx)secx
dydx=secx
Result
dydx=secx

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?