Expert Answer to "f(x)=x/1+x g(x)=sin2x"

Answered question

2022-01-10

f(x)=x/1+x g(x)=sin2x

nick1337

Expert2022-02-08Added 777 answers

$f \circ g = f (g (x) = \frac{\sin 2 x}{\sin 2 x + 1}$

$\sin 2 x + 1 = 0$

$\sin 2 x = - 1$

$2 x = - \frac{π}{2}$

$x = - \frac{π}{4}$

all $x$ excpet $x = - \frac{π}{4}$

$g \circ f = g (f (x) = g (\frac{x}{1} + x) = \sin (2 (\frac{x}{1} + x)$

allx excpet x = -1

$f \circ f = f (\frac{x}{1} + x) = \frac{x}{1} + \frac{x}{1} + \frac{x}{1} + x = \frac{x}{1} + x + x = \frac{x}{2} x + 1$

all $x$ except $x = - \frac{1}{2}$

$g \circ g = g (g (x)) = g (\sin 2 x) = \sin 2 (\sin 2 x));$

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