Explained: "What is the slope of the line tangent..."

Jakob Tanner

Answered question

2022-03-14

What is the slope of the line tangent to the graph of

y = \ln (x^{2})

x = e^{2}

PietAppeteoth22m

Beginner2022-03-15Added 5 answers

\frac{d y}{d x} = m_{\tan \geq n t}

at x=a

\frac{d}{d x} (\ln x) = \frac{1}{x}

differentiate using the chain rule

\frac{d}{d x} (\ln (f (x))) = \frac{1}{f (x)} \times f^{'} (x)

y = \ln (x^{2})

\Rightarrow \frac{d y}{d x} = \frac{1}{x^{2}} \times \frac{d}{d x} (x^{2})

= \frac{2}{x}

x = e^{2} \to \frac{d y}{d x} = \frac{2}{e^{2}}

Result:
slope

= \frac{2}{e^{2}}

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