What is the instantaneous rate of change for

fun9vk

fun9vk

Answered question

2022-03-17

What is the instantaneous rate of change for g(x)=x2x+4 when x=-7?

Answer & Explanation

Emmy Dorsey

Emmy Dorsey

Beginner2022-03-18Added 2 answers

Find g'(-7)
Use the power rule: ddx(xn)=nxn1
g(x)=2x211x11+0(4x01)
g'(x)=2x-1
Again, find the instantaneous rate of change by computing g'(-7).
g'(-7)=2(-7)-1=-14-1=-15
Alexa Lewis

Alexa Lewis

Beginner2022-03-19Added 5 answers

x2x+4,x=7
ddx(x2x+4)=2x1
x=-7
(ddx(x2x+4))|{(x=7)}=(2x1)|(x=7)=15
Therefore, the instantaneous rate of change of f(x)=x2x+4 at x=-7 is -15.
Answer:
-15

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