markush35q

2022-04-03

Suppose that $f\left(x\right)={t}^{2}+3t-7$ . What is the average rate of change of f (x) over the interval 5 to 6?

jmroberts70pbo2

Beginner2022-04-04Added 10 answers

Explanation:

The average rate of change of a function is the same as the total change over the total time, i.e. the rate is

$\stackrel{\u2015}{r}=\frac{\mathrm{\u25b3}f\left(x\right)}{\mathrm{\u25b3}x}=\frac{f\left(6\right)-f\left(5\right)}{6-5}=f\left(6\right)-f\left(5\right)=47-33=14$

The average rate of change of a function is the same as the total change over the total time, i.e. the rate is

Melody Gamble

Beginner2022-04-05Added 10 answers

Explanation:

the average rate of change is a measure of the slope of the secant line in the closed interval [a,b]

average rate of change$=\frac{f\left(b\right)-f\left(a\right)}{b-a}$

here [a,b]=[5,6]

f(b)=f(6)=36+18-7=47

f(a)=f(5)=25+15-7=33

$\Rightarrow \frac{47-33}{6-5}=14$

the average rate of change is a measure of the slope of the secant line in the closed interval [a,b]

average rate of change

here [a,b]=[5,6]

f(b)=f(6)=36+18-7=47

f(a)=f(5)=25+15-7=33

Find the local maximum and minimum values and saddle points of the function. If you have three-dimensional graphing software, graph the function with a domain and viewpoint that reveal all the important aspects of the function

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