What is the equation of the normal line

Willie Kelley

Willie Kelley

Answered question

2022-04-07

What is the equation of the normal line of f(x)=x4+2x3x29x3 at x=-1?

Answer & Explanation

Kaitlynn Craig

Kaitlynn Craig

Beginner2022-04-08Added 13 answers

f(-1)=-1-2-1+9-3=2
f(x)=4x3+6x22x9
so f'(-1)=4+6+2-9=3
The slope of the tangent line at (-1, 2) is 3, so the normal line has slope 13.
The line with slope m=13 through the point (-1,2) is
y2=13(x(1))
y2=13x13
y=13x+53

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