How do you find the average rate of change for the function f(x)=x2−2x on the indicated intervals [1,3]?

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chabinka61jx · Accepted Answer

So, in this case we havef(3)=9-6=3 and f(1)=1-2=-1And the average rate of change isf(3)−f(1)3−1=3−(−1)3−1=42=2The average rate of change of function f on interval [a,b] isf(b)−f(a)b−aIt is the ratio of the changes, it may also be written △f△x and it may be thought of as the slope of the line through the endpoints of the graph of f on the interval.Algebraically it is one version of the difference quotient. (The quotient of the differences in f values and x values)

aludirao09au · Accepted Answer

f(x)=x2−2x,[1,3]The average rate of change of f(x) on the interval [a,b] is f(b)−f(a)b−aWe have that a=1,b=3,f(x)=x2−2xThus, f(b)−f(a)b−a=−2(3)+(3)2−(−21+12)3−(1)=2Answer: the average rate of change is 2.

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