How do you find the equation of the

Kali Thomas

Kali Thomas

Answered question

2022-04-13

How do you find the equation of the line tangent to f(x)=x22x3 at the point (-2,5)?

Answer & Explanation

fonne0kgq

fonne0kgq

Beginner2022-04-14Added 11 answers

The equation of a line in point-slope form is
yy1=m(xx1)
where m represents the gradient and (x1,y1) a point on the line
here we have (-2 ,5) a point on the line and require to find m.
For f(x) the gradient is found by obtaining f'(x) and evaluating
for x=-2.
f(x)=x22x3f(x)=2x2
and f(2)=2(2)=6=m
Using m=-6 and (x1,y1)=(2,5) substitute into equation.
y5=6(x+2)y5=6x12
y=6x7 is the equation of the tangent line

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