How do you find the instantaneous rate of

Eddie Clarke

Eddie Clarke

Answered question

2022-04-18

How do you find the instantaneous rate of change for h(t)=5t2+20t+1 for t=2?

Answer & Explanation

Kaphefsceasiaf8w9

Kaphefsceasiaf8w9

Beginner2022-04-19Added 9 answers

h'(t)=-10t+20 so h(2)=10(2)+20=0, so zero is the instantaneous rate of change at t=2.
libertydragonrbha

libertydragonrbha

Beginner2022-04-20Added 15 answers

Explanation:
The instantaneous rate of change for a function is the derivative of that function.
Given: h(t)=5t2+20t+1.
The derivative is h'(t)=-10t+20
So at t=2, the rate of change is:
h'(2)=-10*2+20
=-20+20
=0
Therefore, there is no change at t=2.

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