What is the average value of 20+10xe^{-\frac{x}{3}} over the interval

Eddie Clarke

Eddie Clarke

Answered question

2022-04-19

What is the average value of 20+10xex3 over the interval of 0< x <15?

Answer & Explanation

ysnlm8eut

ysnlm8eut

Beginner2022-04-20Added 14 answers

The given function is continuous in the closed interval [0,15]
Average rate of change in (0,15)=f(15)f(0)150
=(20+150e15)2015
=10e5
Average rate of change in (0,15)=10e5

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