What is the average value of the function f(x)=(x-1)^{2} on

Charlotte Holden

Charlotte Holden

Answered question

2022-04-17

What is the average value of the function f(x)=(x1)2 on the interval [1,5]?

Answer & Explanation

cadhail6n1t

cadhail6n1t

Beginner2022-04-18Added 14 answers

f(x)=(x1)2=x22x+1
Average of all points of f(x)[a,b]=abf(x)dxba
15(x22x+1)dx=[x33x2+x]15=[53352+5][131+1]
=65313=643
6434=163

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