Using the limit definition, how do you find the derivative

Dashawn Robbins

Dashawn Robbins

Answered question

2022-04-22

Using the limit definition, how do you find the derivative of y=x2+x+1?

Answer & Explanation

eldgamliru9x

eldgamliru9x

Beginner2022-04-23Added 16 answers

Explanation:
Find f(a+h)=(a+h)2+(a+h)+1=a2+2ah+h2+a+h+1 and
f(a)=a2+a+1 then plug it in to the formula limh0f(a+h)f(a)h and then simplify. Remember to put in 0 for h after you factor out h from the numerator and cancel it to the h in the denominator. The remaining terms are your answer.
Jamison Newman

Jamison Newman

Beginner2022-04-24Added 10 answers

The limit definition tells us that:
y=limh0f(x+h)f(x)h
where h is a small increment.
In our case we get:
limh0[(x+h)2+(x+h)+1][x2+x+1]h=
=limh0x2+2xh+h2+x+h+1x2x1h=
limh0(h2x+h+1h)=limh0(2x+h+1)=
as h0 we get:
y'=2x+1

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