Integrate solution: \int(\frac{\tan^{-1}x}{x-\tan^{-1}x})^2dx

Slade Higgins

Slade Higgins

Answered question

2022-04-24

Integrate solution:
(tan1xxtan1x)2dx

Answer & Explanation

louran20z47

louran20z47

Beginner2022-04-25Added 14 answers

With x=tan(u),dx=1cos2(u)du, thus
(tan1xxtan1x)2dx=(utan(u)u1cos(u))2du
Now, observe that
d(1sin(u)ucos(u))=usin(u)du(sin(u)ucos(u))2
This allows to integrate by parts:
=1x(1+(1+x2)arctan(x)xarctan(x))+C=1+xarctan(x)xarctan(x)+C

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?