Calcule <munder> <mo movablelimits="true" form="prefix">lim <mrow class="MJX-TeXAtom-ORD"

kunyatia33

kunyatia33

Answered question

2022-05-22

Calcule lim x 0 ( 1 x 2 x sin 3 ( x ) ) without using L'Hospital

Answer & Explanation

zepplinkid7yk

zepplinkid7yk

Beginner2022-05-23Added 11 answers

lim x 0 ( 1 x 2 x sin 3 x ) = lim x 0 ( sin 3 x x 3 x 2 sin 2 x ) = lim x 0 ( x 3 sin 3 x ) ( 1 x 2 ) ( sin 3 x x 3 1 ) = 1 lim x 0 ( 1 x 2 ) ( sin x x 1 ) ( sin 2 x x 2 + sin x x + 1 ) = 1 lim x 0 ( sin x x x 3 ) 3 = 1 ( 1 6 ) 3 = 1 2

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