Series expression of <msubsup> &#x222B;<!-- ∫ --> 0 <mi mathvariant="normal">&#x221E;

Summer Bradford

Summer Bradford

Answered question

2022-06-24

Series expression of 0 e x 1 + e x d x

Answer & Explanation

Ryan Newman

Ryan Newman

Beginner2022-06-25Added 26 answers

If you do the substitution e x = t and e x d x = d t, then your integral becomes
1 0 1 1 + t d t = 0 1 1 1 + t d t = 0 1 1 t + t 2 t 3 + d t = 1 1 2 + 1 3 1 4 +

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