skilpadw3

2022-07-25

The home range, in hectares, of a carnivorous mammal weighing w grams can be approximated by $H(w)=0.11{w}^{1.36}$

a)Find the average rate at which a carnivorous mammal's home range increases as the animal's weight grows from 200g to 450g.

b) Find $\frac{H(500)-H(400)}{500-400}$, and interpret this result.

a)Find the average rate at which a carnivorous mammal's home range increases as the animal's weight grows from 200g to 450g.

b) Find $\frac{H(500)-H(400)}{500-400}$, and interpret this result.

slapadabassyc

Beginner2022-07-26Added 21 answers

$H(w)=0.11{w}^{1.36}.$

$a)\frac{H(200)-H(450)}{200-450}=\frac{(148.181)-(446.439)}{200-450}=1.19303$

$b)\frac{H(500)-H(400)}{500-400}=\frac{515.219-380.36}{500-400}=1.3486$

$a)\frac{H(200)-H(450)}{200-450}=\frac{(148.181)-(446.439)}{200-450}=1.19303$

$b)\frac{H(500)-H(400)}{500-400}=\frac{515.219-380.36}{500-400}=1.3486$

Kenya Leonard

Beginner2022-07-27Added 6 answers

PART A>>>

Av rate = [ H(450) - H(200)] / (450 - 200)

= [ 446.44 - 148.18 ] / 250

= 298.26 / 250

= 1.193 hectacres/gram.

PART B>>> Av rate = [ 515.22 -380.36 ] / 100 = 134.86/100 = 1.35 hectacres/gram.

Av rate = [ H(450) - H(200)] / (450 - 200)

= [ 446.44 - 148.18 ] / 250

= 298.26 / 250

= 1.193 hectacres/gram.

PART B>>> Av rate = [ 515.22 -380.36 ] / 100 = 134.86/100 = 1.35 hectacres/gram.

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