Express the equation in exponential form. a) log 3 ⁡ ( 27 ) = 3b) log 3 ⁡ ( 1 ) = 0

As by the definition of logarithm we know thatA number 'x' is said to be the logarithm of a number 'N' to the base 'a'iff ( log a ⁡ N = x ) ⇔ a x = NhereExponential form of(a) log 3 ⁡ ( 27 ) = 3 ⇒ 3 3 = 27(which is the required exponential form)

And this answer for (b)(b) log 3 ⁡ 1 = 0 ⇒ 3 0 = 1(which is the required exponential form).

As by the definition of logarithm we know thatA number 'x' is said to be the logarithm of a number 'N' to the base 'a'iff ( log a ⁡ N = x ) ⇔ a x = NhereExponential form of(a) log 3 ⁡ ( 27 ) = 3 ⇒ 3 3 = 27(which is the required exponential form)

And this answer for (b)(b) log 3 ⁡ 1 = 0 ⇒ 3 0 = 1(which is the required exponential form).

"Express the equation in exponential form. a) log..." was answered by our community

High School
Calculus and Analysis
Calculus 1
Logarithmic Functions

Karley Castillo

Answered question

2022-11-11

Express the equation in exponential form.
a)

\log_{3} (27) = 3

\log_{3} (1) = 0

Answer & Explanation

luthersavage6lm

Beginner2022-11-12Added 22 answers

As by the definition of logarithm we know that
A number 'x' is said to be the logarithm of a number 'N' to the base 'a'
iff

(\log_{a} N = x) \Leftrightarrow a^{x} = N

here
Exponential form of
(a)

\log_{3} (27) = 3 \Rightarrow 3^{3} = 27

(which is the required exponential form)

InjegoIrrenia1mk

Beginner2022-11-13Added 3 answers

And this answer for (b)
(b)

\log_{3} 1 = 0 \Rightarrow 3^{0} = 1

(which is the required exponential form).

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