Let C be the curve of intersection of the parabolic cylinder x^2 = 2y, and the surface 3z = xy. Find the exact length of C from the origin to the point (2, 2, 4/3).

ingerentayQL

ingerentayQL

Answered question

2022-11-24

Let C be the curve of intersection of the parabolic cylinder x 2 = 2 y, and the surface 3 z = x y. Find the exact length of C from the origin to the point (2, 2, 4/3).

Answer & Explanation

Jimmy Sandoval

Jimmy Sandoval

Beginner2022-11-25Added 9 answers

x 2 = 2 y
can be written as
y = x 2 2
let x=t
y = t 2 2
3 z = x y
z = 3 x y
z = t t 2 2 3 = t 3 6
r ( t ) =< x ( t ) , y ( t ) , z ( t ) > r ( t ) =< t , t 2 2 , t 3 6 >
r ( t ) = d d t < t , t 2 2 , t 3 6 >=< d d t ( t ) , d d t ( t 3 6 ) >=< 1 , t , t 2 2 >
| r ( t ) | = 1 2 + t 2 + ( t 2 2 ) 2 | r ( t ) | = ( 1 + t 2 2 ) 2 | r ( t ) | = ( 1 + t 2 2 )
Origin is at t=0
(2,2,4/3) is at t=2
Length of the curve
L = a b | r ( t ) | d t L = 0 2 ( 1 + t 2 2 ) d t L = [ t + t 3 3 2 ] 0 2 L = [ 2 + 2 3 3 2 0 ] L = [ 2 + 4 3 ] L = 10 3

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