Suppose that a population develops according to the logistic equation \frac{dP}{dt}=0.05P-0.0005P^2 where t is measured in weeks. What is the carrying capacity? What is the value of k?

Ayaana Buck

Ayaana Buck

Answered question

2021-06-12

Suppose that a population develops according to the logistic equation
dPdt=0.05P0.0005P2
where t is measured in weeks. What is the carrying capacity? What is the value of k?

Answer & Explanation

liannemdh

liannemdh

Skilled2021-06-13Added 106 answers

Logistic differential equation:
dPdt=kP(1PM)
where M is carrying capacity
Hence, to obtain M and k we need to rewrite the given equation:
dPdt=0.05P0.0005P2
=0.05P(10.01P)
=0.05P(1P100)
Therefore we have:
dPdt=0.05P(1P100)
And from this equation we get:
k=0.05M=100

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