ffortunyu

2021-11-27

Find two different sets of parametric equations for a rectangular equation

$y-{x}^{2}-3$

Phisecome

Beginner2021-11-28Added 18 answers

Step 1

We have

1)$y={x}^{2}-3$

Let$x=t$ and put it in equation(1), we get

$y={t}^{2}-3$

Again, let$x={t}^{3}$ and put it in equation (1), we get

$\Rightarrow y={\left({t}^{3}\right)}^{2}-3$

$\Rightarrow y={t}^{6}-3$

Hence, the two different sets of parametric equations are

$y={t}^{2}-3$

$y={t}^{6}-3$

We have

1)

Let

Again, let

Hence, the two different sets of parametric equations are

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