Terrie Lang

2021-12-28

Evaluate the definite integral.

${\int}_{2}^{3}{2}^{x}dx$

Stella Calderon

Beginner2021-12-29Added 35 answers

Step 1

To evaluate the given integral,

${\int}_{2}^{3}{2}^{x}dx$

Solution:

The given integral is,${\int}_{2}^{3}{2}^{x}dx$

Solving integral we get,

$\int}_{2}^{3}{2}^{x}dx={\frac{{2}^{x}}{\mathrm{log}2}}_{2}^{3$

$=\frac{{2}^{3}-{2}^{2}}{\mathrm{log}2}$

$=\frac{8-4}{\mathrm{log}2}$

Step 2

further solving we get,

${\int}_{2}^{3}{2}^{x}dx=4\mathrm{log}2$

Hence, the value of integral is$\frac{4}{\mathrm{log}2}$ .

To evaluate the given integral,

Solution:

The given integral is,

Solving integral we get,

Step 2

further solving we get,

Hence, the value of integral is

Kirsten Davis

Beginner2021-12-30Added 27 answers

Given:

${\int}_{2}^{3}{2}^{x}dx$

Integral of exponential function:

$\int {a}^{x}dx=\frac{{a}^{x}}{\mathrm{ln}\left(a\right)}$ at a=2:

$=\frac{{2}^{x}}{\mathrm{ln}\left(2\right)}$

Answer:

$=\frac{{2}^{x}}{\mathrm{ln}\left(2\right)}+C$

Integral of exponential function:

Answer:

Vasquez

Expert2022-01-07Added 669 answers

Return the limits

Calculate the expression

Simplify

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