Concepcion Hale

2022-01-07

Given $\int ({x}^{5}-3{x}^{4}+6{x}^{3}+3)dx$ , evaluate the indefinite integral.

Beverly Smith

Beginner2022-01-08Added 42 answers

Step 1

The given integral is$\int ({x}^{5}-3{x}^{4}+6{x}^{3}+3)dx$ .

obtain the integral value as follows.

$\int ({x}^{5}-3{x}^{4}+6{x}^{3}+3)dx=\int {x}^{5}dx-\int 3{x}^{4}dx+\int 6{x}^{3}dx+\int 3dx$

$=\frac{{x}^{6}}{6}-3\left(\frac{{x}^{5}}{5}\right)+6\left(\frac{{x}^{4}}{4}\right)+3x+C$

$=\frac{{x}^{6}}{6}-\frac{3{x}^{5}}{5}+\frac{3{x}^{4}}{2}+3x+C$

Thus, the value of the integral is$\frac{{x}^{6}}{6}-\frac{3{x}^{5}}{5}+\frac{3{x}^{4}}{2}+3x$

Step 2

Answer:

The value of the given integral is$\left(\frac{{x}^{6}}{6}\right)-3\left(\frac{{x}^{5}}{5}\right)+3\left(\frac{{x}^{4}}{2}\right)+3x$ .

The given integral is

obtain the integral value as follows.

Thus, the value of the integral is

Step 2

Answer:

The value of the given integral is

ambarakaq8

Beginner2022-01-09Added 31 answers

Given integral.

$\int {x}^{5}-3{x}^{4}+6{x}^{3}+3dx$

$\int {x}^{5}dx-\int 3{x}^{4}dx+\int 6{x}^{3}dx+\int 3dx$

Evaluate

$\frac{{x}^{6}}{6}-\frac{3{x}^{5}}{5}+\frac{3{x}^{4}}{2}+3x$

Add C

Answer:

$\frac{{x}^{6}}{6}-\frac{3{x}^{5}}{5}+\frac{3{x}^{4}}{2}+3x+C$

Evaluate

Add C

Answer:

karton

Expert2022-01-11Added 613 answers

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