Find convergence of: \sum_{n=1}^\infty\frac{1}{(n!)^{2/n}}

Myah Fuller

Myah Fuller

Answered question

2022-02-26

Find convergence of:
n=11(n!)2n

Answer & Explanation

Spandri3uv

Spandri3uv

Beginner2022-02-27Added 7 answers

We have
en=1+n1!+n22!++nnn!+>nnn!
Then
1n!<ennn
so1n!2n<e2n2
and probably you can take it from here.

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