Solve the equation: \(\displaystyle{x}{\left({2}{y}+{1}\right)}{\left.{d}{x}\right.}={y}{\left({x}^{{2}}-{3}{x}+{2}\right)}{\left.{d}{y}\right.}\)

siliciooy0j

siliciooy0j

Answered question

2022-03-21

Solve the equation:
x(2y+1)dx=y(x23x+2)dy

Answer & Explanation

Nunnaxf18

Nunnaxf18

Beginner2022-03-22Added 18 answers

Step 1
You want to get all the y stuff to one side, and all the x stuff to the other. These are called "separable equations" for this reason.
x(2y+1)dx=y(x23x+2)dy
xx23x+2dx=y2y1dy
xx23x+2dx=y2y1dy
Now we integrate.
The left side looks like partial fraction decomposition and the right side looks like a u-sub with u=2y1.
sorrisi7yny

sorrisi7yny

Beginner2022-03-23Added 9 answers

Step 1
There is a mistake when you divide both sides by
(2y+1)(x23x+2)
The correct form is
xx2-3x+2dx=y2y+1dy
so integrating both sides gives
2ln|x2|ln|x1|=14((2y+1)ln|2y+1|+C )

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