I am trying to find the common ratio

loraliyeruxi

loraliyeruxi

Answered question

2022-04-01

I am trying to find the common ratio of n=02nzn2

Answer & Explanation

Cailyn Hanson

Cailyn Hanson

Beginner2022-04-02Added 11 answers

Let us be systematic about how we find the ratio of consecutive terms. The terms are given by an=zn22n so the ratio is
an+1an=z(n+1)22n+12nzn2=z(n+1)2n22=z2n+12.
Note that this value changes with each n so it is not "common", and this series is not a geometric series.

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