Solving \(\displaystyle{y}^{{{\left({2}\right)}}}-{5}{y}^{{{\left({1}\right)}}}+{4}{y}={\frac{{{1}}}{{{e}^{{x}}+{1}}}}\).

palmantkf4u

palmantkf4u

Answered question

2022-04-01

Solving y(2)5y(1)+4y=1ex+1.

Answer & Explanation

ineditablesdmx0

ineditablesdmx0

Beginner2022-04-02Added 9 answers

You can also proceed as follows:
y5y+4y=11+ex (y4y)(y4y)=11+ex   (y4y)(y4y)=11+ex   zz=11+ex   (exz)=1e2x+ex

Laylah Hebert

Laylah Hebert

Beginner2022-04-03Added 15 answers

Step 1
dx=duu
ddxex+1=dduu(u+1)=(d1ud1u+1)du
Step 2
ddxe3x(ex+1)=dduu4(u+1)=(d1u4d1u3+d1u2d1u+d1u+1)du

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