Integrating trig function &#x222B;<!-- ∫ --> <mrow class="MJX-TeXAtom-ORD"> <msqrt>

patzeriap0

patzeriap0

Answered question

2022-05-23

Integrating trig function ( sin 2 x ) 2 + ( 2 sin x cos x ) 2 d x = sin 2 x sin 2 x + 4 sin 2 x cos 2 x d x

Answer & Explanation

Stacy Johns

Stacy Johns

Beginner2022-05-24Added 8 answers

sin 2 x sin 2 x + 4 sin 2 x cos 2 x d x = sin 2 x ( sin 2 x + 4 cos 2 x ) d x = { sin x ( sin 2 x + 4 cos 2 x ) d x , sin x 0 sin x ( sin 2 x + 4 cos 2 x ) d x , sin x < 0 = { sin x ( 1 + 3 cos 2 x ) d x , sin x 0 sin x ( 1 + 3 cos 2 x ) d x , sin x < 0 = { 1 3 sin x ( 1 + 3 cos 2 x ) d ( 3 cos x ) , sin x 0 1 3 sin x ( 1 + 3 cos 2 x ) d ( 3 cos x ) , sin x < 0
Now say z = 3 cos x. Then the integration becomes
= { 1 3 sin x 1 + z 2 d z , sin x 0 1 3 sin x 1 + z 2 d z , sin x < 0

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