I have the following problem A = <munderover> &#x2211;<!-- ∑ --> <mrow class="MJX-Te

lobht98

lobht98

Answered question

2022-06-21

I have the following problem
A = n = 1 2 n + 7 n 2 n + 6 n

Answer & Explanation

Lisbonaid

Lisbonaid

Beginner2022-06-22Added 22 answers

If however you want to use the comparison test you are pretty close
2 n + 7 n 2 n + 6 n > 7 n 2 n + 6 n > 7 n 6 n + 6 n = 1 2 7 n 6 n
And so your since 7 6 > 1, you can say the series of the right diverge, and hence your series is larger than a divergent, and hence divergent.

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