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Jaqueline Kirby

Jaqueline Kirby

Answered question

2022-06-19

Suppose that a function f ( x ) is differentiable x [ a , b ]. Prove that f ( x ) takes on every value between f ( a ) and f ( b ).

If the above question is a misprint and wants to say "prove that f ( x ) takes on every value between f ( a ) and f ( b )", then I have no problem using the intermediate value theorem here.

If, on the other hand, it is not a misprint, then it seems to me that I can't use the Intermediate value theorem, as I can't see how I am authorised to assume that f ( x ) is continuous on [ a , b ].

Or perhaps there is another way to look at the problem?

Answer & Explanation

Arcatuert3u

Arcatuert3u

Beginner2022-06-20Added 30 answers

This is not a misprint. You can indeed prove that f takes every value between f ( a ) and f ( b ). You cannot, however, assume that f is continuous. A standard example is f ( x ) = x 2 sin ( 1 / x ) when x 0, and 0 otherwise. This function is differentiable at 0 but the derivative isn't continuous at it.
To prove the problem you have, consider the function g ( x ) = f ( x ) λ x for any λ ( f ( a ) , f ( b ) ). What do you know about g ( a ), g ( b )? What do you conclude about g in the interval [ a , b ]?

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