I cant understand how to prove this question. We learned about intermediate value theorem but this m

Brunton39

Brunton39

Answered question

2022-06-26

I cant understand how to prove this question. We learned about intermediate value theorem but this makes no sense because 120 km isn't in bounds of either upper or lower limit. Here is the question

At 2:00 PM, a car's speedometer reads 30km/h. At 2:10 PM, it reads 50 km/h. Show that at some time between 2:00 and 2:10 the acceleration was exactly 120 km/ h 2 (YES she wrote the question are h 2 . I hope its a typo). Indicate which theorem you must use in your explanation.

Answer & Explanation

crociandomh

crociandomh

Beginner2022-06-27Added 19 answers

50  km / hr 30  km / hr 1 / 6  hr = 20 1 / 6   km hr 2 .
There's no typo; acceleration can be measured in kilometers per hour per hour, written as km / hr 2 , or in meters per second per second, written as m / sec 2 , etc.

Acceleration is the derivative of velocity with respect to time. So you have velocity at one point in time, minus velocity at another point in time, divided by elapsed time, equals the derivative of velocity with respect to time at some time between those two points in time. A standard theorem deals with that.
Emmy Knox

Emmy Knox

Beginner2022-06-28Added 10 answers

First, convert the units of your time axis to hours: say 2:00 =0, and 2:10 =1/6. What does the mean value say about the acceleration (= derivative of velocity) for the endpoint values 30 and 50 respectively? I don't want to give too much away.

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