Yesenia Obrien

2022-07-01

How do you find the volume of $y={x}^{2}$ going from [0,2] on the x-axis and [0,4] on the y-axis?

Jasper Parsons

Beginner2022-07-02Added 7 answers

Volume $=\pi \int {x}^{2}dy$, with y from 2 to 4 and x from $y={x}^{2}$

$=\pi \int ydy$, with y from 2 to 4

$=\pi [\frac{{y}^{2}}{2}]$, between the limits 2 and 4

$=\frac{\pi}{2}({4}^{2}-{2}^{2})=6\pi $ cubic units.

$=\pi \int ydy$, with y from 2 to 4

$=\pi [\frac{{y}^{2}}{2}]$, between the limits 2 and 4

$=\frac{\pi}{2}({4}^{2}-{2}^{2})=6\pi $ cubic units.

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