Awainaideannagi

2022-07-28

Differentiate the function.

$g(x)=3{x}^{-3}({x}^{4}-3{x}^{3}+15x-4)$

$g(x)=3{x}^{-3}({x}^{4}-3{x}^{3}+15x-4)$

Anaya Gregory

Beginner2022-07-29Added 14 answers

distribute $(3{x}^{-3})\text{}to\text{}{x}^{4}-3{x}^{3}+15x-4$

so that simplifies to $3x-9+45{x}^{-2}-12{x}^{3}$

now differentiate the above funt

$g(x)=3x-9+45{x}^{-2}-12{x}^{3}$

${g}^{\prime}(x)=3-0-90x-36{x}^{2}$

${g}^{\prime}(x)=3-90x-36{x}^{2}$

so that simplifies to $3x-9+45{x}^{-2}-12{x}^{3}$

now differentiate the above funt

$g(x)=3x-9+45{x}^{-2}-12{x}^{3}$

${g}^{\prime}(x)=3-0-90x-36{x}^{2}$

${g}^{\prime}(x)=3-90x-36{x}^{2}$

Donna Flynn

Beginner2022-07-30Added 3 answers

$g(x)=3{x}^{-3}({x}^{4}-3{x}^{3}+15x-4)$

First multiply $g(x)=3{x}^{-3}({x}^{4}-3{x}^{3}+15x-4)=3x-9+45{x}^{-2}-12{x}^{-3}$

Now differentiate using the power rule which is $\frac{d}{dx}[{x}^{n}]=n{x}^{n-1}$

So, ${g}^{\prime}(x)=3-90{x}^{-3}+36{x}^{-4}\text{}or\text{}{g}^{\prime}(x)=3-\frac{90}{{x}^{3}}+\frac{36}{{x}^{4}}$

First multiply $g(x)=3{x}^{-3}({x}^{4}-3{x}^{3}+15x-4)=3x-9+45{x}^{-2}-12{x}^{-3}$

Now differentiate using the power rule which is $\frac{d}{dx}[{x}^{n}]=n{x}^{n-1}$

So, ${g}^{\prime}(x)=3-90{x}^{-3}+36{x}^{-4}\text{}or\text{}{g}^{\prime}(x)=3-\frac{90}{{x}^{3}}+\frac{36}{{x}^{4}}$

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