Prove that the below equation has a root in the given interval: cos(sqrt x)=e^x−2 in the interval (0,1)." So I found that f(1)=0.54 and f(0)=1 for the left hand side. But this did not seem to be the same as the right hand side. So how exactly can I prove it is continuous in the interval, and possibly go further and prove the presence of a root?

sittesf

sittesf

Answered question

2022-08-10

MathJax(?): Can't find handler for document MathJax(?): Can't find handler for document Prove that the below equation has a root in the given interval: cos ( x ) = e x 2 in the interval (0,1)." f ( 1 ) = 0.54 and f ( 0 ) = 1 for the left hand side.

Answer & Explanation

Marlie Frazier

Marlie Frazier

Beginner2022-08-11Added 14 answers

defining
f ( x ) = cos ( x ) e x + 2
then we have
f ( 0 ) = 2
and
f ( 1 ) = cos ( 1 ) e + 2 0.17797 < 0
it is
x 0.9419081484

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