Show that x+y+z ge 3 for all (x,y,z)in R^3 such that x>0, y>0, z>0, and xyz=1.

Ashlynn Hale

Ashlynn Hale

Answered question

2022-08-08

Show that x + y + z 3 for all ( x , y , z ) R 3 such that x > 0, y >0, z > 0, and xyz = 1.

Answer & Explanation

wijnvatid

wijnvatid

Beginner2022-08-09Added 16 answers

Take x + y + z 3...(1)
and we have x y z = 1 x = 1 / y z
y = 1 / x z both values are substitute in eqn (1)
1 y z + y + z 3
x + 1 x z + z 3
subtracting above two eqns
1 y z 1 x z + y x 0
x y x y z x y
1 x y z
1 1 0 (given xyz=1)
0 = 0.

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