How to distinguish linear differential equations from nonlinear ones? I know, that e.g.: y''-2y=ln(x) is linear, but 3+yy'=x-y is nonlinear. Why?
garzettaiy
Open question
2022-08-19
How to distinguish linear differential equations from nonlinear ones? I know, that e.g.: is linear, but is nonlinear. Why?
Answer & Explanation
Daniella Cochran
Beginner2022-08-20Added 12 answers
Linear differential equations are those which can be reduced to the form , where L is some linear operator. Your first case is indeed linear, since it can be written as: While the second one is not. To see this first we regroup all y to one side: then we simply notice that the operator is not linear (for example we can take two functions and and notice that .
hercegvm
Beginner2022-08-21Added 3 answers
If the equation would have had on the right, that also would have made it non-linear, since natural logs are non-linear functions. Remember that this has its roots in linear algebra: . You can analyse functions term-by-term to determine if they are linear, if that helps. The first time a term is non-linear, then the entire equation is non-linear. Remember that the xs can pretty much do or appear however they want, since they're independent. Which means if you can't tell just by glancing, try to group all your y terms to one side and then analyse them. Makes it much easier. See, I was also overthinking this, but realised you have to go back to those definitions we're given. Two criteria for linearity: 1.The dependent variable y and its derivatives are of first degree; the power of each y is 1. 2. Each coefficient depends only on the independent variable x. makes it nonlinear as has been said, because that coefficient on is not x. Had that coefficient been a constant, you would have been correct to call it linear, since constants can be functions of x. Like, . Its graph is a line, i.e. linear function.