Use the properties of integrals to evaluate integral 0 to 1 (4+3x^2)dx

firestopper53sh

firestopper53sh

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2022-08-17

Use the properties of integrals to evaluate integral 0 to 1 (4+3x2)dx

Answer & Explanation

Alison Mcgrath

Alison Mcgrath

Beginner2022-08-18Added 9 answers

Step 1
Given: I=01(4+3x2)dx
for evaluating given integral, first we separate terms then integrate it
Step 2
so,
01(4+3x2)dx=401dx+301x2dx   (xndx=xn+1n+1+c)
=4[x]01+3[x33]01
=4(10)+(1303)
=4(1)+1
=4+1
=5
hence, value of given integral is equal to 5.

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